Given $N (p) = 60 p - p^{2}$ $N(p)=60p-p^2$ , how do you find N(9)?

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Answer 1 · 2017-01-07T17:49:33

Substitute $9$ $color(red)(9)$ for each occurrence of $p$ $color(red)(p)$ in the function. See below for full process.

Given $N (p) = 60 p - p^{2}$ $N(color(red)(p)) = 60color(red)(p) - color(red)(p)^2$

The

$N (9) = (60 \times 9) - 9^{2}$ $N(color(red)(9)) = (60 xx color(red)(9)) - color(red)(9)^2$

$N (9) = 540 - 81$ $N(color(red)(9)) = 540 - 81$

$N (9) = 459$ $N(color(red)(9)) = 459$

Given N(p)=60p-p^2N(p)=60p−p2N(p)=60p-p^2, how do you find N(9)?