Given: $p(x) = -5absx + abs(-x + 1$ , $h(x) = -x^2 - 3x$ , and $g(x) = 5 - sqrt(x+30)$ , how do you find g(-34)?

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Answer 1 · 2015-05-26T11:23:38

Note that the formulas for $p(x)$ and $h(x)$ are extraneous.

Given $g(x) = 5-sqrt(x+30)$

Therefore
$g(color(red)(-34)) = 5 - sqrt(color(red)(-34) +30)$

$g(-34) = 5-2i$

Given: p(x) = -5absx + abs(-x + 1p(x) = -5absx + abs(-x + 1, h(x) = -x^2 - 3xh(x) = -x^2 - 3x, and g(x) = 5 - sqrt(x+30)g(x) = 5 - sqrt(x+30), how do you find g(-34)?