Given: $p (x) = - 5 | x | + | - x + 1 |$ $p(x) = -5absx + abs(-x + 1$ , $h (x) = - x^{2} - 3 x$ $h(x) = -x^2 - 3x$ , and $g (x) = 5 - \sqrt{x + 30}$ $g(x) = 5 - sqrt(x+30)$ , how do you find p(3)?

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Answer 1 · 2015-05-25T17:13:43

The functions $h (x)$ $h(x)$ and $g (x)$ $g(x)$ appear to be extraneous.

Given $p (x) = - 5 | x | + | - x + 1 |$ $p(x) = -5abs(x) + abs(-x+1)$

$p (3) = - 5 | 3 | + | - 3 + 1 |$ $p(3) = -5abs(3) + abs(-3+1)$

$= - 15 + 2$ $= -15 + 2$

$= - 13$ $= -13$

Given: p(x) = -5absx + abs(-x + 1p(x)=−5|x|+|−x+1|p(x) = -5absx + abs(-x + 1, h(x) = -x^2 - 3xh(x)=−x2−3xh(x) = -x^2 - 3x, and g(x) = 5 - sqrt(x+30)g(x)=5−√x+30g(x) = 5 - sqrt(x+30), how do you find p(3)?