Given point (-5,12) how do you find the distance of the point from the origin, then find the measure of the angle in standard position whose terminal side contains the point?

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Answer 1 · 2017-09-15T11:51:43

Distance of point from origin is $13$ unit and is at an angle of
$247.38^0$ from $0^0$

Point is at $(-5 ,12)$ and origin is at $(0,0)$ , We know

the distance between two points $(x_1,y_1) and (x_2 , y_2)$ is

$D= sqrt((x_1-x_2)^2 + (y_1-y_2)^2)$ or

$D= sqrt((-5-0)^2 + (12-0)^2) = sqrt 169 =13$ . The point is on

$3$ rd quadrant . $tan alpha = 12/5 :. alpha = tan^-1(12/5)$ or

$alpha= 67.38^0 :. theta = 180+ 67.38 = 247.38^0$

Distance of point from origin is $13$ unit and is at an angle of

$247.38^0$ from $0^0$ [Ans]