Question

Given `sectheta=5` and `tantheta=2sqrt6`, how do you find `cot(90^circ-theta)`?

Answer 1

`cot(90^@-theta)=2sqrt6`

Explanation:

As `cot(90^@-theta)=tantheta`

`cot(90^@-theta)=2sqrt6`

Note there is no need to use `sectheta=5`