Given $tan θ = \frac{3}{4}$ $tantheta=3/4$ and $π < θ < \frac{3 π}{2}$ $pi<theta<(3pi)/2$ , how do you find $tan 2 θ$ $tan2theta$ ?

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Answer 1 · 2017-08-07T14:33:34

$\frac{24}{7} .$ $24/7.$

We know that, $tan 2 θ = \frac{2 tan θ}{1 - {tan}^{2} θ} .$ $tan2theta=(2tantheta)/(1-tan^2theta).$

$:. tan2theta=(2*3/4)/(1-9/16)=3/2*16/7=24/7.$

Given tantheta=3/4tanθ=34tantheta=3/4 and pi<theta<(3pi)/2π<θ<3π2pi<theta<(3pi)/2, how do you find tan2thetatan2θtan2theta?