Given that #f(x)=(x-2)^5+2(x-2)^4+3(x-2)^3+4(x-2)^2+5(x-2)+6#. If #f(x)=a(color(red)(x+2))^5+b(x-2)^4+c(x-2)^3+d(x-2)^2+e(x-2)+f#. Find the values of #a,b,c,d,e,f# ?
Note that the question is #a(x+2)^5# and not #a(x-2)^5# , which makes me have no clue how to solve it...
Note that the question is
1 Answer
Jun 26, 2017
See below.
Explanation:
Calling
we have
Solving for