Question

Given that the length of a parallelogram is `(x^2-5x)` and the width is `(2x^2+x+3)`, how do you find the area of the figure in terms of x?

Answer 1

`(x^2-5x)(2x^2+x+3)`

Explanation:

Area = length X width

`=(x^2-5x)(2x^2+x+3)`

I understand width as height.