Given the equation $2 H_{2} O \to 2 H_{2} + O_{2}$ $2H_2O -> 2H_2 + O_2$ , how many moles of $H_{2} O$ $H_2O$ be required to produce 2.5 moles of $O_{2}$ $O_2$ ?

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Given the equation $2 H_{2} O \to 2 H_{2} + O_{2}$ $2H_2O -> 2H_2 + O_2$ , how many moles of $H_{2} O$ $H_2O$ be required to produce 2.5 moles of $O_{2}$ $O_2$ ?

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Answer 1 · 2016-03-24T10:13:31

From the equation you'll see that $2 H_{2} O$ $2H_2O$ gives $1 O_{2}$ $1O_2$

Explanation:

So every 2 molecules of water gives 1 molecule of oxygen.
This ratio ( $2 : 1$ $2:1$ ) stays the same if we are talking about moles, because a mole is a set number of molecules ( $\approx 6.02 \times 10^{23}$ $~~6.02xx10^23$ ). This goes for any substance.
So to produce 2.5 moles of oxygen, you will need the double number of moles of water, i.e. 5 moles.

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Given the equation $2 H_{2} O \to 2 H_{2} + O_{2}$ $2H_2O -> 2H_2 + O_2$ , how many moles of $H_{2} O$ $H_2O$ be required to produce 2.5 moles of $O_{2}$ $O_2$ ?

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Given the equation $2 H_{2} O \to 2 H_{2} + O_{2}$ $2H_2O -> 2H_2 + O_2$ , how many moles of $H_{2} O$ $H_2O$ be required to produce 2.5 moles of $O_{2}$ $O_2$ ?