Given the function $f (r) = \sqrt{r + 1} - 5$ $f(r)=sqrt(r+1)-5$ , what is f(x-1)?

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Answer 1 · 2016-12-28T14:04:11

$f (x - 1) = \sqrt{x} - 5$ $f(x-1)=sqrtx-5$

$f (r) = \sqrt{r + 1} - 5$ $f(r)=sqrt(r+1)-5$

$f (x - 1)$ $f(x-1)" "$ means replace every $r$ $r$ by $(x - 1)$ $(x-1)$

$f (x - 1) = \sqrt{x - 1 + 1} - 5$ $f(x-1)=sqrt(x-1+1)-5$

$f (x - 1) = \sqrt{x} - 5$ $f(x-1)=sqrtx-5$

Given the function f(r)=sqrt(r+1)-5f(r)=√r+1−5f(r)=sqrt(r+1)-5, what is f(x-1)?