Given the molar mass of the compound is 186.5 g and the empirical formula is C2H7, what is its molecular formula?

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Given the molar mass of the compound is 186.5 g and the empirical formula is C2H7, what is its molecular formula?

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Answer 1 · 2015-11-03T08:44:24

The molecular formula is always a multiple of the empirical formula.

Explanation:

So ${(E F)}_{n} = M F$ $(EF)_n = MF$ . All we have to do is solve for $n$ $n$ .

i.e. ${(2 \times 12.011 + 7 \times 1.00794)}_{n} \cdot g \cdot m o l^{- 1} = 186.5 \cdot g \cdot m o l^{- 1}$ $(2xx12.011 + 7 xx 1.00794)_n*g*mol^(-1) = 186.5*g*mol^(-1)$ . So solve for $n$ $n$ , and then do the product $(C_{2} H_{7}) \times n$ $(C_2H_7) xx n$ to give the molecular formula. Please repost the answer here.

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Given the molar mass of the compound is 186.5 g and the empirical formula is C2H7, what is its molecular formula?

1 Answer

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