Given the nuclear equation $_{1}^{1} H + X \to_{3}^{6} L i +_{2}^{4} H e$ $""_1^1H + X -> _3^6Li + _2^4He$ , what is the particle represented by $X$ $X$ ?

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Given the nuclear equation $_{1}^{1} H + X \to_{3}^{6} L i +_{2}^{4} H e$ $""_1^1H + X -> _3^6Li + _2^4He$ , what is the particle represented by $X$ $X$ ?

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Answer 1 · 2018-04-08T14:39:07

$_{4}^{9} B e$ $""_4^9Be$

Explanation:

We have the nuclear equation:

$_{1}^{1} H + X \to_{3}^{6} L i +_{2}^{4} H e$ $""_1^1H+X->""_3^6Li+""_2^4He$

In a nuclear equation, the total mass and the number of protons stay the same.

There is only $1$ $1$ mass unit on the left side, but $6 + 4 = 10$ $6+4=10$ units on the left side. This tells us element $X$ $X$ has a mass of $10 - 1$ $10-1$ units.

Also, there is only $1$ $1$ proton on the left side, but $3 + 2 = 5$ $3+2=5$ protons on the right side. So, element $X$ $X$ must have $5 - 1 = 4$ $5-1=4$ protons.

The element with four protons on the periodic table is beryllium, and its symbol is $B e$ $Be$ . Thus, the complete equation for this reaction is:

$_{1}^{1} H +_{4}^{9} B e \to_{3}^{6} L i +_{2}^{4} H e$ $""_1^1H+""_4^9Be->""_3^6Li+""_2^4He$

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Given the nuclear equation $_{1}^{1} H + X \to_{3}^{6} L i +_{2}^{4} H e$ $""_1^1H + X -> _3^6Li + _2^4He$ , what is the particle represented by $X$ $X$ ?

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Given the nuclear equation 11H+X→63Li+42He""_1^1H + X -> _3^6Li + _2^4He, what is the particle represented by XX?

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Given the nuclear equation $_{1}^{1} H + X \to_{3}^{6} L i +_{2}^{4} H e$ $""_1^1H + X -> _3^6Li + _2^4He$ , what is the particle represented by $X$ $X$ ?