Question

Given the point `P(sqrt2/2, sqrt2/2)`, how do you find `sintheta` and `costheta`?

Answer 1

Cal P (sqrt2/2, sqrt2/2) the terminal point of the arc t.
The radius of the circle will be:
`OP = sqrt(2/4 + 2/4) = sqrt(4/4) = 2/2 = 1`
That is the radius of the unit circle. There for:
`sin t = (sqrt3/2)`
`cos t = (sqrt3)/2`
tan t = 1
cot = 1
`sec t = 2/(sqrt3) = (2sqrt3)/3`
`csc t = 2/(sqrt3) = (2sqrt3)/3`