Given the reaction of 0.25 g of Al with HCl, how many liters of #H_2# gas will be produced if the temperature is 40 C and the pressure is 1.15 atm?

Question

#2Al_((s)) + 6HCl_((aq)) -> 3H_(2(aq)) + 2AlCl_(3(aq))#

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Answer 1 · 2017-01-18T08:09:16

Approx. #300*mL" of dihydrogen"#

You have the stoichiometric equation. We work out the molar equivalence of aluminum metal,

#"Moles of Al"# #=# #(0.25*g)/(27.0*g*mol^-1)=9.26xx10^-3*mol#

#"Moles of dihydrogen"# #=# #3/2xx9.26xx10^-3*mol=0.0139*mol#

And #V=(nRT)/P#, where #n=0.0139*mol#, so............

#(0.0139*cancel(mol)xx0.0821*L*cancel(atm)*cancel(K^-1)*cancel(mol^-1)xx313*cancelK)/(1.15*cancel(atm))#

#=??L#