Given $x^{5}$ $x^5$ if x<0 and 2x + 1 if x >= 0, how do you find f(0)?

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Given $x^{5}$ $x^5$ if x<0 and 2x + 1 if x >= 0, how do you find f(0)?

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Answer 1 · 2016-08-07T13:17:12

$\Rightarrow f (0) = 0 + 1 = 1$ $=>f(0)=0+1 = 1$

Explanation:

I think they call this a 'stepwise solution'

$f (0)$ $f(0)$ means that you assign the value of 0 to $x$ $x$

Condition 1: if $x < 0$ $x<0$ then you apply the calculation $x^{5}$ $x^5$

Condition 2: if $x \geq 0$ $x>=0$ then you apply the calculation $2 x + 1$ $2x+1$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
We are given the value of $x$ $x$ as 0

Condition 1 is that $x$ $x$ must be less than 0 so as $x = 0$ $x=0$ this equation does not apply.

Condition 2 is that $x$ $x$ can be 0 or grater than 0. So as $x = 0$ $x=0$ this equation is the one we use.

$\Rightarrow f (0) \to 2 x + 1$ $=>f(0)->2x+1$

$\Rightarrow f (0) = 2 (0) + 1$ $=>f(0)=2(0)+1$

$\Rightarrow f (0) = 0 + 1 = 1$ $=>f(0)=0+1 = 1$

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1 Answer

Explanation:

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