Given #x=bz+cy;" " y=az+cx and z=ay+bx# how will you prove #x^2/(1-a^2)=y^2/(1-b^2)=z^2/(1-c^2)#?
1 Answer
Dec 19, 2016
See below.
Explanation:
solving for couples we obtain
(1-1)
(1-2)
(1-3)
From (1-1)
From (1-2)
and also
then follows