Question

Here is the chemical reaction - Ca(NO3)2 + (NH4)3PO4 --> Double displacement follows... If you start with 10.25 mL of .553M Ca(NO3)2 soln, how many moles of calcium nitrate do you have in the soln? Also a part 2 in the question.

Answer 1

We got `5.67xx10^-3*mol` with respect to calcium nitrate,,,

Explanation:

Bt definition...`"Concentration"="Moles of solute"/"Volume of solution"`

And thus `"moles of solute"="concentration"xx"volume"`

`=10.25xx10^-3*Lxx0.553*mol*L^-1=??*mol`

Note that this molar quantity of calcium biphosphate would precipitate from this solution.....

`Ca^(2+) + HPO_4^(2-) rarr CaHPO_4(s)darr`