Hi there! Can you take a few minutes to help me out please? Thank you!

enter image source here

1 Answer
CW
Sep 26, 2017

#b=4sqrt22# units,
#angleA=9.1^@#
#angleB=80.9^@#

Explanation:

enter image source here

Given that #DeltaABC# is right-angled at #C#, #=> AB# is the hypotenuse, as shown in the figure.
By Pythagorean theorem,
#c^2=a^2+b^2#,
#=> b^2=c^2-a^2#
#=> b=sqrt(c^2-a^2)=sqrt(19^2-3^2)=sqrt352=sqrt(16xx22)=4sqrt22#
#=> b=4sqrt22~~18.8# units

#SinangleA=(BC)/(AB)=a/c=3/19#
#=> angleA=sin^-1(3/19)=9.08^@=9.1^@# (to the nearest tenth)

#=> angleB=90-9.1=80.9^@#

Related questions
Impact of this question
859 views around the world
You can reuse this answer
Creative Commons License