How can I deduce the balance equation for magnesium sulphide using half equation method(ion-electron method)???

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Answer 1 · 2017-06-12T16:53:00

Do you refer to $"steel-making..........."??$

Sulfur is removed from pig iron by the following reaction with magnesium..........

$Mg(l) + 1/8S_8(s) rarr MgS(s)$

I am told that the powdery magnesium sulfide floats atop of the liquid steel, and is then removed from the blast furnace.

If I wanted to represent this by means of half equations, I would separate the individual redox equations......

$"Oxidation (i):"$ $Mg rarr Mg^(2+) rarr 2e^(-)$

$"Reduction (ii):"$ $S +2e^(-) rarr S^(2-)$

$"Overall (i) + (ii):"$ $Mg(s) + S(s) rarr MgS(s)$