How can I find the derivative of $y = c^{x}$ $y=c^x$ using first principles, where c is an integer?

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Answer 1 · 2014-10-17T02:14:00

By rewriting a bit,

$y = c^{x} = e^{(ln c) x}$ $y=c^x=e^{(lnc)x}$ .

$y'=e^{(lnc)x}cdot(lnc)=(lnc)c^x$

I hope that this was helpful.

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