How do I find the asymptotes of #y=-1/x^2#?
1 Answer
Sep 13, 2015
Horizontal asymptote at:
Vertical asymptote at:
Explanation:
The horizontal asymptote is at :
So in this case:
as x tends to infinity the denominator keeps getting larger and
larger forcing the fraction to tend to zero, hence: the horizontal
asymptote is at
The vertical asymptote(s) are the at the value(s) of x that make the
function
case is at: