How do I find the derivative of #f(x)=ln (x^3+3)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Guilherme N. Jan 2, 2016 Using chain rule, which states that #(dy)/(dx)=(dy)/(du)(du)/(dx)# Explanation: Renaming #u=x^3+3#, we can differentiate it now, as #f(x)ln(u)# #(dy)/(dx)=1/u(3x^2)=(3x^2)/(x^3+3)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1429 views around the world You can reuse this answer Creative Commons License