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How do I find the logarithm of 16 in base 2?

1 Answer

Oct 15, 2014

${log}_{2} 16 = x$ $log_2 16 = x$

$\Rightarrow 2^{x} = 16$ $=> 2^x = 16$

$\Rightarrow 2^{x} = 2^{4}$ $=> 2^x = 2^4$

$\Rightarrow x = 4$ $=> x = 4$

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