How do I find the quotient #(-5+i)/(-7+i)#? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer Hriman Mar 4, 2018 #(18-i)/25# Explanation: Multiply by the conjugate #(-5+i)/(-7+i)*(-7-i)/(-7-i)=# #(35-2i-(-1))/(49-(-1))=# #(36-2i)/50=# #(18-i)/25# Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of #12/(5i)#? How do I rationalize the denominator of a complex quotient? How do I divide #6(cos^circ 60+i\ sin60^circ)# by #3(cos^circ 90+i\ sin90^circ)#? How do you write #(-2i) / (4-2i)# in the "a+bi" form? Write the complex number #8/(1+i)# in standard form? See all questions in Division of Complex Numbers Impact of this question 9186 views around the world You can reuse this answer Creative Commons License