How do I find the value of x?Do the side lengths form a pythagorean triple?

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How do I find the value of x?Do the side lengths form a pythagorean triple?

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Answer 1 · 2017-03-16T01:16:47

$20$ $20$

Explanation:

Yes, the sides form a triple (it is a $3, 4, 5$ $3,4,5$ triangle, except on a bigger scale ( $4$ $4$ times bigger)).

By the Pythagorean Theorem,

$a^{2} + b^{2} = c^{2}$ $a^2+b^2=c^2$ .

In this case,
$12^{2} + 16^{2} = c^{2}$ $12^2+16^2=c^2$
$400 = c^{2}$ $400=c^2$ , and since $c$ $c$ is a side length, it must be the positive answer to the square root, or $20$ $20$ .

Answer 2 · 2017-03-16T01:29:14

$x = 20$ $x=20$ ; See link

Explanation:

Use the Pythagorean theorem ( $a^{2} + b^{2} = c^{2}$ $a^2+b^2=c^2$ )

Lets label the right triangle such that:
$a = 12$ $a= 12$
$b = 16$ $b=16$
$c = x$ $c=x$

Thus,

$12^{2} + 16^{2} = x^{2}$ $12^2+16^2=x^2$

$144 + 256 = x^{2}$ $144+256=x^2$

$400 = x^{2}$ $400=x^2$

$\sqrt{400} = x$ $sqrt(400)=x$

$20 = x$ $20=x$

So our missing side, $c$ $c$ is $20$ $20$

We can now say that the sides of our triangle are $12, 16, 20$ $12,16,20$

I've included a link that lists a couple of Pythagorean triples (a couple because they are infinitely many).

https://www.mathsisfun.com/numbers/pythagorean-triples.html

Answer 3 · 2017-03-16T19:05:45

$x = 20$ $x=20$ , Yes.

Explanation:

$12 = 4 \times 3$ $12 = 4 xx 3$

$16 = 4 \times 4$ $16 = 4 xx 4$ ,

$3$ $3$ , $4$ $4$ , $5$ $5$ is a Pythagorean triple, so

$x = 4 \times 5$ $x = 4 xx 5$

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How do I find the value of x?Do the side lengths form a pythagorean triple?

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