How do I solve f(x)=(x^3-8)/(x^2+5x+6) on a TI-84?

1 Answer
Apr 27, 2018

zero = (2, 0)

Explanation:

Given: f(x) = (x^3 - 8)/(x^2 + 5x + 6)

On a TI-84 select the Y= key and enter in the function

" " Y1 = (x^3 - 8)/(x^2 + 5x + 6)

Make sure your WINDOW is in 6:ZStandard

2nd QUIT (above MODE)

GRAPH key (lower right of screen)

To find the solution you are finding x-intercepts (zeros).

2ND CALC (TRACE key) 2:zero

Left Bound? Select a point below the x-axis using the arrow keys, then hit ENTER

Right Bound? Select a point above the x-axis using the arrow keys, then hit ENTER

Guess? ENTER (you can move closer to the x-intercept, but it isn't necessary unless there are two zeros close to each other).

Zero = (2, 0)