How do I prove that $2/(cotxtan2x) -= 1 - tan^2x$ ?

Question

1608 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-20T14:09:05

As proved below.

$cot x = 1/ tan x$

$tan 2x = (2 tan x) / (1 - tan^2 x)$ - Identity.

To prove $2 / (cot x * tan 2x) = 1 - tan^2 x$

$2 / (cot x * tan 2x)$

=> (2 tan x) / tan 2x#

$=> (2 tan x) / ((2tan x) / (1 - tan^2 x))$

$=> (1 - tan^2 x) = R H S$

How do I prove that 2/(cotxtan2x) -= 1 - tan^2x2/(cotxtan2x) -= 1 - tan^2x?