How do i prove that #csc 2x+cot 2x=cot x#?

I tried doing it:

#1/(sin2x)+1/(tan2x)#

#=1/(2sinx cost)+1/(2tan x/(1-tan^2 x)#

#=1/(2 sin x cos x)+(1-tan^2 x)/(2 tan x#

Can someone help please?