How do I simplify this in terms of x?

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How do I simplify this in terms of x?

Simplify in terms of x

${((\sqrt[3]{x + 1} - 7) + 7)}^{3} - 1$ $((root3(x+1)-7)+7)^3-1$

1 Answer

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Answer 1 · 2018-03-12T19:22:45

$x$ $x$

Explanation:

First cube every term in the big bracket (cubing cancels out the cube root):
$(x + 1 - 7^{3} + 7^{3}) - 1$ $(x + 1 - 7^3 + 7^3) - 1$
The $7^{3}$ $7^3$ is cancelled out to give
$x + 1 - 1 = x$ $x + 1 - 1 = x$

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How do I simplify this in terms of x?

Simplify in terms of x

${((\sqrt[3]{x + 1} - 7) + 7)}^{3} - 1$ $((root3(x+1)-7)+7)^3-1$

1 Answer

Explanation:

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How do I simplify this in terms of x?

Simplify in terms of x ((3√x+1−7)+7)3−1((root3(x+1)-7)+7)^3-1

1 Answer

Explanation:

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Simplify in terms of x

${((\sqrt[3]{x + 1} - 7) + 7)}^{3} - 1$ $((root3(x+1)-7)+7)^3-1$