How do I simplify #(x^2-5x+6)/(x^2-4)*(x^2+3x+2)/(x^2-2x-3)#?

1 Answer
Nallasivam V
Aug 9, 2015

The answer to the problem is 1.

Explanation:

Factorize both denominator and Numerator.
= #(x^2 - 2x -3x +6)/((x + 2) (x - 2))# . #(x^2 + x + 2x +2)/(x^2 - 3x + x -3)#

= #(x(x - 2) -3( x - 2))/((x + 2) (x - 2))# . #(x(x + 1) +2 (x + 1))/(x(x - 3) + 1 (x -3)#

= #((x - 2) ( x - 3))/((x + 2) (x - 2))# . #((x + 1) (x + 2))/((x - 3) (x + 1)# = 1

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