How do I solve #(2^x)^x=10#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Alan N. Oct 16, 2017 #x approx +- 1.822616# Explanation: #(2^x)^x = 10# #2^(x^2) =10# #x^2 log_10 2= 1# #x^2 = 1/log_10 2 approx 3.321928# #x approx +- sqrt 3.321928# # approx +- 1.822616# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 2727 views around the world You can reuse this answer Creative Commons License