How do I solve #log_sqrt5##0.2#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Ratnaker Mehta Oct 14, 2017 # -2.# Explanation: We know that, #log_a y=x iff a^x=y.# #"So, if, "log_sqrt5 0.2=x," then, "(sqrt5)^x=0.2.# #:. (5^(1/2))^x=0.2=2/10=1/5.# #:. 5^(x/2)=5^(-1).# #:. x/2=-1.# #:. x=-2.# # rArr log_sqrt5 0.2=-2.# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 1548 views around the world You can reuse this answer Creative Commons License