How do pi bonds overlap?

1 Answer
Jul 20, 2018

Two (unhybridized) pp orbitals overlap sideways ("lateral-ly") to form a pi (piπ) bond.

Explanation:

Molecules containing bonds of orders higher than one (i.e., double and triple bonds) contain piπ bonds. For example, each molecule of ethene "H"_2 "C" = "C" "H"_2H2C=CH2 contains a carbon-carbon "C"="C"C=C double bond.

Each neutral carbon atom contains four valence electrons. The atom undergoes a hybridization process that would result in three sp^2sp2 orbitals and one 2p2p orbital before bonding to another carbon atom of an identical configuration and forming a carbon-carbon double bond.

Carbon valence shell before and after hybridization, created with Google Drawings

As seen in the diagram, the 2p2p orbital that is left half-filled and not hybridized is capable of overlapping with an equally half-filled and unhybridized 2p2p orbital from another carbon atom.

Sigma and pi bonds, CK-12 Foundation - Zachary Wilson

The two 2p2p orbitals overlap in parallel ("sideway") to the bonding axis between the two nuclei and the sigma bond from the overlapping of two sp^2sp2 orbitals. Note that each pp orbital contains two petal-like electron clouds such that "two"two regions of high electron density on opposite sides of the bonding axis (shown in blue in the second diagram) makes a single piπ bond.