How do solve #-5/(x+3)^2>0# graphically?

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Answer 1 · 2016-12-07T10:45:56

There is no solution.

Is the question correct? Have you got the inequality round the correct way?

Set #" "y=-5/((x+3)^2) >0#

The question requires that #y>0#

Observation that the graph implies that as #x# tends to #+-oo# #y# tends to 0

However, the question states that we require #y>0#

Clearly there is no #y# greater than 0 so #color(red)("there is no solution")#

Consider the graph:

Tony N