How do solve the following linear system?: $2 x - 4 y = 3, 3 x - 5 y = 61$ $2x - 4y =3, 3x-5y=61$ ?

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Answer 1 · 2018-04-09T10:53:43

Solution: $x = 114.5, y = 56.5$ $x=114.5 , y= 56.5$

$2 x - 4 y = 3 (1), 3 x - 5 y = 61 (2)$ $2x-4y=3 (1) , 3x-5y=61 (2)$ Multiplied equation (1) by $3$ $3$

and equation (2) by $2$ $2$ we get,

$6 x - 12 y = 9 (3), 6 x - 10 y = 122 (4)$ $6x-12y=9 (3) , 6x-10y=122 (4)$ , sbtracting equation (3)

from equation (4) we get, $2y=113 :.y = 56.5$ . Substituting

$y = 56.5$ in equation (1) we get, $2x-4*56.5=3$ or

$2x-226=3 or 2x =229 or x= 114.5$

Solution: $x=114.5 , y= 56.5$ [Ans]

How do solve the following linear system?: 2x - 4y =3, 3x-5y=61 2x−4y=3,3x−5y=61 2x - 4y =3, 3x-5y=61 ?