How do solve the following linear system?: $2 x - 4 y = 9, 2 x - 5 y = 3$ $2x - 4y=9, 2x - 5y=3$ ?

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How do solve the following linear system?: $2 x - 4 y = 9, 2 x - 5 y = 3$ $2x - 4y=9, 2x - 5y=3$ ?

1 Answer

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Answer 1 · 2015-12-27T23:58:55

I found:
$x = \frac{33}{2}$ $x=33/2$
$y = 6$ $y=6$

Explanation:

I would isolate $2 x$ $2x$ from the first equation:
$2 x = 9 + 4 y$ $2x=9+4y$
and substitute into the second:
$9 + 4 y - 5 y = 3$ $9+4y-5y=3$
rearranging:
$y = 6$ $y=6$
back into the first equation:
$2 x = 9 + 24$ $2x=9+24$
$x = \frac{33}{2}$ $x=33/2$

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How do solve the following linear system?: $2 x - 4 y = 9, 2 x - 5 y = 3$ $2x - 4y=9, 2x - 5y=3$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do solve the following linear system?: 2x−4y=9,2x−5y=3 2x - 4y=9, 2x - 5y=3 ?

1 Answer

Explanation:

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How do solve the following linear system?: $2 x - 4 y = 9, 2 x - 5 y = 3$ $2x - 4y=9, 2x - 5y=3$ ?