Step 1) Because the second equation is already solved for yy we can substitute (4x + 4)(4x+4) for yy in the first equation and solve for xx:
3x + 2y = 123x+2y=12 becomes:
3x + 2(4x + 4) = 123x+2(4x+4)=12
3x + (2 xx 4x) + (2 xx 4) = 123x+(2×4x)+(2×4)=12
3x + 8x + 8 = 123x+8x+8=12
(3 + 8)x + 8 = 12(3+8)x+8=12
11x + 8 = 1211x+8=12
11x + 8 - color(red)(8) = 12 - color(red)(8)11x+8−8=12−8
11x + 0 = 411x+0=4
11x = 411x=4
(11x)/color(red)(11) = 4/color(red)(11)11x11=411
(color(red)(cancel(color(black)(11)))x)/cancel(color(red)(11)) = 4/11
x = 4/11
Step 2) Substitute 4/11 for x in the second equation and solve for y:
y = 4x + 4 becomes:
y = (4 xx 4/11) + 4
y = 16/11 + 4
y = 16/11 + (4 xx 11/11)
y = 16/11 + 44/11
y = (16 + 44)/11
y = 60/11
The Solution Is:
x = 4/11 and y = 60/11
Or
(4/11, 60/11)
