How do solve the following linear system?: 3x - y = -6, y = 5x - 73xy=6,y=5x7?

1 Answer
Aug 27, 2017

See a solution process below: (13/2, 51/2)(132,512)

Explanation:

Step 1) Because the second equation is already solved for yy we can substitute (5x - 7)(5x7) for yy in the first equation and solve for xx:

3x - y = -63xy=6 becomes:

3x - (5x - 7) = -63x(5x7)=6

3x - 5x + 7 = -63x5x+7=6

(3 - 5)x + 7 = -6(35)x+7=6

-2x + 7 = -62x+7=6

-2x + 7 - color(red)(7) = -6 - color(red)(7)2x+77=67

-2x + 0 = -132x+0=13

-2x = -132x=13

(-2x)/color(red)(-2) = (-13)/color(red)(-2)2x2=132

(color(red)(cancel(color(black)(-2)))x)/cancel(color(red)(-2)) = 13/2

x = 13/2

Step 2) Substitute 13/2 for x in the second equation and calculate y:

y = 5x - 7 becomes:

y = (5 * 13/2) - 7

y = 65/2 - (2/2 xx 7)

y = 65/2 - 14/2

y = 51/2

The Solution Is: x = 13/2 and y = 51/2 or (13/2, 51/2)