How do solve the following linear system?: $5 x + 2 y = 2, 3 x - y = - 6$ $5x+2y=2, 3x - y = -6$ ?

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Answer 1 · 2015-11-24T22:46:06

$(- \frac{10}{11}, \frac{36}{11})$ $(-10/11,36/11)$

Multiply the second equation by $2$ $2$ .

${(5x+2y=2),(6x-2y=-12):}$

Add the equations.

$11x=-10$

$color(blue)(x=-10/11$

Plug the newfound value for $x$ in to either equation to determine $y$ .

$5x+2y=2=>5(color(blue)(-10/11))+2y=2$

$-50/11+2y=22/11$

$2y=72/11$

$color(green)(y=36/11$

Write the answers in an ordered pair: $(-10/11,36/11)$

How do solve the following linear system?: 5x+2y=2, 3x - y = -6 5x+2y=2,3x−y=−6 5x+2y=2, 3x - y = -6 ?