How do solve the following linear system?: $5 x - 3 y = - 29, x - 3 y = - 6$ $5x - 3y = -29 , x - 3y = -6$ ?

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How do solve the following linear system?: $5 x - 3 y = - 29, x - 3 y = - 6$ $5x - 3y = -29 , x - 3y = -6$ ?

1 Answer

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Answer 1 · 2015-12-08T03:31:40

$(- 2, \frac{1}{12})$ $(-2, 1/12)$

Explanation:

$x - 3 y = - 6$ $x-3y=-6$
$x = 3 y - 6$ $x=3y-6$

plug in $x$ $x$ for $5 x - 3 y = - 29$ $5x-3y=-29$
$5 (3 y - 6) - 3 y = - 29$ $5(3y-6)-3y=-29$
$15 y - 30 - 3 y = - 29$ $15y-30-3y=-29$
$12 y = 1$ $12y=1$
$y = \frac{1}{12}$ $y=1/12$

plug in $y$ $y$ in $x = 3 y - 6$ $x=3y-6$ to find $x$ $x$
$x = 3 (\frac{1}{12}) - 6$ $x=3(1/12)-6$
$x = 4 - 6$ $x=4-6$
$x = - 2$ $x=-2$

$(- 2, \frac{1}{12})$ $(-2, 1/12)$

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How do solve the following linear system?: $5 x - 3 y = - 29, x - 3 y = - 6$ $5x - 3y = -29 , x - 3y = -6$ ?

1 Answer

Explanation:

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How do solve the following linear system?: 5x - 3y = -29 , x - 3y = -6 5x−3y=−29,x−3y=−65x - 3y = -29 , x - 3y = -6 ?

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Explanation:

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How do solve the following linear system?: $5 x - 3 y = - 29, x - 3 y = - 6$ $5x - 3y = -29 , x - 3y = -6$ ?