How do solve the following linear system?: $6 x+3y=11 , x+y=6$ ?

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Answer 1 · 2016-02-10T03:34:44

$x=-7/3$ , $y=25/3$

Please refer to some of my earlier replies. To solve a system of two linear equations in two variables you have to first eliminate one of variables.

The equations are $6x+3y=11$ and $x+y=6$ .

Multiplying latter by 3 gives us $3x+3y=18$ .

Now subtracting first equation $6x+3y=11$ from $3x+3y=18$
gives us $3x=-7$ or $x=-7/3$

Putting $x=-7/3$ in $x+y=6$ gives us

$y=6-x$ or $y=6-(-7/3)$ , which gives us

$y=25/3$

How do solve the following linear system?: 6 x+3y=11 , x+y=6 6 x+3y=11 , x+y=6 ?