How do solve the following linear system?: $x + 4 y = 3, x + 2 y = 1$ $x+4y=3 , x+2y=1$ ?

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How do solve the following linear system?: $x + 4 y = 3, x + 2 y = 1$ $x+4y=3 , x+2y=1$ ?

1 Answer

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Answer 1 · 2017-01-09T18:25:24

$x = \frac{5}{3}$ $x = 5/3$
$y = \frac{1}{3}$ $y = 1/3$

Explanation:

x + 4y = 3 (1)
x - 2y = 1 (2)
Subtract (2) from (1), we get
6y = 2
$y = \frac{2}{6} = \frac{1}{3}$ $y = 2/6 = 1/3$
$x = 1 + 2 y = 1 + \frac{2}{3} = \frac{5}{3}$ $x = 1 + 2y = 1 + 2/3 = 5/3$

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How do solve the following linear system?: $x + 4 y = 3, x + 2 y = 1$ $x+4y=3 , x+2y=1$ ?

1 Answer

Explanation:

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How do solve the following linear system?: x+4y=3 , x+2y=1x+4y=3,x+2y=1 x+4y=3 , x+2y=1?

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Explanation:

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How do solve the following linear system?: $x + 4 y = 3, x + 2 y = 1$ $x+4y=3 , x+2y=1$ ?