How do you #(16x^2)/(4x^5)#?

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Answer 1 · 2015-07-20T19:20:15

#(16x^2)/(4x^5)=4/x^3#

#(16x^2)/(4x^5)#

Simplify #16/4# to #4#.

#(4x^2)/(x^5)#

Apply the exponent rule #a^m/a^n=a^(m-n)#.

#(4x^2)/x^5=4x^(2-5)=4x^(-3)#

Apply the exponent rule #a^(-m)=1/(a^m)#

#4x^(-3)=4/x^3#