Question

How do you add `(-3+i) + (4+6i)`?

Answer 1

`1+7i`. See explanation below

Explanation:

The addition in `CC` is defined by

`(a+bi)+(c+di)=(a+c)+(b+d)i`. The two complex numbers addition consists in adding real parts and imaginary parts separately.

In our case

`(-3+i)+(4+6i)=(-3+4)+(1+6)i` because the imaginary part of first complex number is 1. Then we have:

`(-3+4)+(1+6)i=1+7i`