How do you add $6 \sqrt{3} + 5 \sqrt{2} - 2 \sqrt{3} - \sqrt{2}$ $6sqrt3 + 5sqrt2 - 2sqrt3 - sqrt2$ ?

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How do you add $6 \sqrt{3} + 5 \sqrt{2} - 2 \sqrt{3} - \sqrt{2}$ $6sqrt3 + 5sqrt2 - 2sqrt3 - sqrt2$ ?

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Answer 1 · 2015-04-11T21:16:56

Add together similar roots like $\sqrt{3}$ $sqrt(3)$ or $\sqrt{2}$ $sqrt(2)$ to get:
$6 \sqrt{3} - 2 \sqrt{3} = 4 \sqrt{3}$ $6sqrt(3)-2sqrt(3)=4sqrt(3)$
and
$5 \sqrt{2} - 1 \sqrt{2} = 4 \sqrt{2}$ $5sqrt(2)-1sqrt(2)=4sqrt(2)$
To finally get:
$4 \sqrt{3} + 4 \sqrt{2} = 4 (\sqrt{3} + \sqrt{2})$ $4sqrt(3)+4sqrt(2)=4(sqrt(3)+sqrt(2))$

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How do you add $6 \sqrt{3} + 5 \sqrt{2} - 2 \sqrt{3} - \sqrt{2}$ $6sqrt3 + 5sqrt2 - 2sqrt3 - sqrt2$ ?

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