How do you balance $A l B r_{3} + K \to K B r + A l$ $AlBr_3+K->KBr+Al$ ?

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How do you balance $A l B r_{3} + K \to K B r + A l$ $AlBr_3+K->KBr+Al$ ?

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Answer 1 · 2016-09-13T15:39:15

$Garbage in must equal garbage out$ $"Garbage in must equal garbage out"$ .

Explanation:

$A l B r_{3} (s) + 3 K (s) \to A l (s) + 3 K B r (s)$ $AlBr_3(s) + 3K(s) rarr Al(s) + 3KBr(s)$

This is actually a redox reaction; however, it does illustrate the required stoichiometry. The given reaction is certainly balanced with respect to mass and charge.

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How do you balance $A l B r_{3} + K \to K B r + A l$ $AlBr_3+K->KBr+Al$ ?

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How do you balance AlBr3+K→KBr+AlAlBr_3+K->KBr+Al?

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Explanation:

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How do you balance $A l B r_{3} + K \to K B r + A l$ $AlBr_3+K->KBr+Al$ ?