How do you balance and translate this reaction: $K C l O_{3} (s) \to K C l (s) + O_{2} (g)$ $KClO_3(s) -> KCl(s) + O_2(g)$ ?

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How do you balance and translate this reaction: $K C l O_{3} (s) \to K C l (s) + O_{2} (g)$ $KClO_3(s) -> KCl(s) + O_2(g)$ ?

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Answer 1 · 2017-05-23T11:08:53

$2 K C l O_{3} (s) \to K C l (s) + 3 O_{2} (g)$ $2KClO_3(s)rarrKCl(s)+3O_2(g)$

Explanation:

Let's identify : K is potassium, Cl is chlorine and O is oxygen.

Let's identify the state symbols : (s) is solid, and (g) is gas.

Let's identify the unbalanced element(s) : Potassium is balanced, there are 1 on each side. Chlorine is balanced, there are 1 on each side. Oxygen is not balanced, there's 3 on the LHS, and 2 on the RHS.

How many times does 2 go into 3? The answer is 1.5. Change the coefficient of the oxygen on the RHS from 1 to 1.5

$K C l O_{3} (s) \to K C l (s) + 1.5 O_{2} (g)$ $KClO_3(s)rarrKCl(s)+1.5O_2(g)$

But we can't have half atoms in chemical equations. Multiply the entire equation by 2 to get rid of the half atom.

$2 K C l O_{3} (s) \to 2 K C l (s) + 3 O_{2} (g)$ $2KClO_3(s)rarr2KCl(s)+3O_2(g)$

Now everything is balanced : There are 2 potassium, 2 chlorine and 6 oxygen atoms.

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How do you balance and translate this reaction: $K C l O_{3} (s) \to K C l (s) + O_{2} (g)$ $KClO_3(s) -> KCl(s) + O_2(g)$ ?

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Explanation:

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How do you balance and translate this reaction: KClO3(s)→KCl(s)+O2(g)KClO_3(s) -> KCl(s) + O_2(g)?

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How do you balance and translate this reaction: $K C l O_{3} (s) \to K C l (s) + O_{2} (g)$ $KClO_3(s) -> KCl(s) + O_2(g)$ ?