Question

How do you balance `Fe(s) + S(s) -> Fe_2S_3(s)`?

Answer 1

`2Fe_(s)` + `3S_(s)` ------------> `Fe_2S_3`

Explanation:

Step 1 : First of all write the equation
`Fe_(s)` + `S_(s)` ------------> `Fe_2S_3`

Step 2 : Now balance the number of `Fe` atoms on both reactant and product side

Here reactant side has one `Fe_(S)` atom and product side has `2` atoms of `Fe_(S)`, therefore multiply `Fe_(S)` at reactant side by `2`

Step 3: Balance `S_(s)`

Here reactant side has one `S_(s)` atom and product side has `3` atoms of `S_(s)`, therefore multiply `S_(s)` at reactant side by `3`

Step 4.
Write the final eqaution

`2Fe_(s)` + `3S_(s)` ------------> `Fe_2S_3`