How do you balance $K O H + B a C l_{2} \to K C I + B a {(O H)}_{2}$ $KOH + BaCl_2 -> KCI + Ba(OH)_2$ ?

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How do you balance $K O H + B a C l_{2} \to K C I + B a {(O H)}_{2}$ $KOH + BaCl_2 -> KCI + Ba(OH)_2$ ?

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Answer 1 · 2016-07-17T10:02:23

$2 K O H + B a C l_{2} \to B a {(O H)}_{2} + 2 K C l$ $2KOH + BaCl_2 rarr Ba(OH)_2 + 2KCl$

Explanation:

Is the given equation stoichiometrically balanced? Does garbage in equal garbage out? In every chemical reaction mass is conserved, and the balanced equation, which after all is our attempt to model an actual chemical process, reflects this.

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How do you balance $K O H + B a C l_{2} \to K C I + B a {(O H)}_{2}$ $KOH + BaCl_2 -> KCI + Ba(OH)_2$ ?

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How do you balance KOH+BaCl2→KCI+Ba(OH)2KOH + BaCl_2 -> KCI + Ba(OH)_2?

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How do you balance $K O H + B a C l_{2} \to K C I + B a {(O H)}_{2}$ $KOH + BaCl_2 -> KCI + Ba(OH)_2$ ?