How do you balance $N a C N + C u C O_{3} \to N a_{2} C O_{3} + C u {(C N)}_{2}$ $NaCN + CuCO_3 -> Na_2CO_3 + Cu(CN)_2$ ?

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How do you balance $N a C N + C u C O_{3} \to N a_{2} C O_{3} + C u {(C N)}_{2}$ $NaCN + CuCO_3 -> Na_2CO_3 + Cu(CN)_2$ ?

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Answer 1 · 2016-03-25T08:13:43

$2 N a C \equiv N (a q) + C u C O_{3} (s) \to N a_{2} C O_{3} (a q) + C u {(C \equiv N)}_{2} (a q)$ $2NaC-=N(aq) + CuCO_3(s) rarr Na_2CO_3(aq) + Cu(C-=N)_2(aq)$

Explanation:

Is the equation above stoichiometrically balanced? Does garbage in equal garbage out? Cyanide treatment of $C u^{2 +}$ $Cu^(2+)$ can lead to reduction, however, given the context of the question, I think the metathesis (partner exchange) reaction is implied.

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How do you balance $N a C N + C u C O_{3} \to N a_{2} C O_{3} + C u {(C N)}_{2}$ $NaCN + CuCO_3 -> Na_2CO_3 + Cu(CN)_2$ ?

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How do you balance NaCN + CuCO_3 -> Na_2CO_3 + Cu(CN)_2NaCN+CuCO3→Na2CO3+Cu(CN)2NaCN + CuCO_3 -> Na_2CO_3 + Cu(CN)_2?

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How do you balance $N a C N + C u C O_{3} \to N a_{2} C O_{3} + C u {(C N)}_{2}$ $NaCN + CuCO_3 -> Na_2CO_3 + Cu(CN)_2$ ?